How can Uranus have storms hot enough to melt steel? A runaway greenhouse effect?

This is amazing considering that Uranus only receives a trifling 3.71 W/m2 energy from the Sun, which per the Stefan-Boltzmann Law is equivalent to a blackbody radiating at a temperature of -183°C, 90°K, or -298°F.

 

How do greenhouse gases violate the 1st law of thermodynamics to amplify 3.71 W/m2 incomingradiation from the Sun to 610,143 W/m2 radiated by a blackbody at 1,538C with peak emission at 1.6 microns, an amplification of outgoing radiation to space over incoming radiation from the Sun by afactor of 83,596 times?

Furthermore, how do greenhouse gases raise the outgoing radiating temperature by 1811°K – 90°K = 1721°K, a temperature increase of more than 20 times? [90°K is the Uranus equilibrium temperature with the Sun]

It’s clearly impossible, unless you program a GIGO climate model to say so. 

 

The real and very simple explanation for this phenomenon is the ideal gas law, not radiative forcing from greenhouse gases, which as the great physicist Maxwell noted, results in a temperature gradient of an atmosphere within a gravity field. 

 

As explained in the basic physics quiz for climate alarmists, 

“the base of the troposphere on the planet Uranus is 320K, considerably hotter than on Earth [288K], despite being nearly 30 times further from the Sun. The base of the troposphere on Uranus is 320K at 100 bars pressure, despite the planet only receiving 3.71 W/m2 energy from the Sun. By the Stefan-Boltzmann Law, a 320K blackbody radiates 584.6 W/m2. This is 157.5 times the energy received from the Sun, due to the atmospheric temperature gradient produced within a planetary gravity field. The temperature at the base of the troposphere is determined by the ideal gas law PV=nRT, where pressure from gravity and atmospheric mass raise the temperature at the base of the troposphere from the equilibrium temperature with the Sun of Uranus of 89.94K to 320K, regardless of the atmospheric mixture of greenhouse gases.”